Mechanical Engineering Programme of Study


 Rafe Bond
 3 years ago
 Views:
Transcription
1 Mechanical Engineering Programme of Study Fluid Mechanics Instructor: Marios M. Fyrillas SOLVED EXAMPLES ON VISCOUS FLOW 1. Consider steady, laminar flow between two fixed parallel plates due to a pressure gradient. Using a control volume of unit depth, height y, and width x (centred at y 0 ) obtain an expression for the velocity profile. a. By integrating the velocity profile obtain an expression for the volumetric flow rate and the mean velocity. b. Obtain an expression for the dimensionless pressure loss as a function of the Reynolds number. w x y Conservation of Momentum of the control volume Consider xmomentum conservation M M F 0 (steadystate so net momentum flux is zero) out in x The forces acting are: i. right surface: pa ii. left surface: pa iii. top surface: A iv. bottom surface: A l t r l t r b b
2 Balance of forces:  pa r r pa l l ( tat bab) Because of symmetry: t b Areas are given by: Ar Al 1 y, At Ab 1 x y( p  p ) x l r du (Newtonian fluid) dy dp constant (pressure increases linearly) dx du dp du yp ( p p) x y dy dx dy Integrate above expression y dp y dp y dp du dy u dy constant dx dx dx To find the constant use the boundary conditions, i.e. at y h and y  h the velocity is zero (u 0) d d u( y h) 0 constant constant= dx dx h p h p y dp h dp h dp y so u=  1 dx dx dx h To find the volumetric flow rate: h h dp y h dp4h Q u d Au 1dy 1 d dx y h dx 3 h 3 h dp 3 dx (mean velocity) u m 3 h dp Q h dp 3 dx A h 3 dx b. Dimensionless pressure drop 3um p 3um 6 1 p h 1 u umh h umh R m umh h e
3 . Working in a similar fashion as for the case of a horizontal cylinder, obtain the velocity profile of Poiseuille s law in an inclined pipe using the control volume suggested in the figure. Conservation of Momentum of the control volume Consider xmomentum conservation M M F 0 (steadystate so net momentum flux is zero) out in x The force balance can be written as: ( pp) r pr r mgsin 0 m r pgsin r du pgsin r du dr dr pgsin pgsin r u rdr cons tant Evaluate the constant using the boundary conditions: pgsin ur R R 4 ( ) 0 0 consta pgsin constant= R 4 nt
4 ( pgsin ) R r u 1 4 R R ( pgsin ) R R r Q uda u rdr 1 r r 0 0 d R ( pgsin ) R R ( pgsin ) R An oil with a viscosity of 0.4 N s/m and density 900 kg/m 3 flows in a pipe of diameter D 0. m. (a) What pressure drop p 1 p, is needed to 5 3 produce a flowrate of Q.010 m /s if the pipe is horizontal with x1 0 and x 10 m? (b) How steep a hill,, must the pipe be on if the oil is to flow through the pipe at the same rate as in part (a), but with p1 p? (c) For the conditions of part (b), if p1 00 kpa, what is the pressure at section x3 5 m where x is measured along the pipe?
5 4. Consider steady, laminar flow in a circular pipe due to a pressure gradient. Using a control volume of length and radius r obtain an expression for the velocity profile. Follow the steps below: a. Consider the control volume below (Figure 1) and indicate the forces exerted on the control volume. Give a physical explanation. Control Volume Figure 1: Laminar flow in a circular pipe. a. Doing a force balance show that the momentum equation can be simplified to: p. r c. Assuming laminar flow of a Newtonian fluid and applying an appropriate boundary condition obtain that the velocity profile is: pd r u 1 16 D d. Integrate above expression to find the volumetric flow rate.. The forces acting on the control volume are the shear forces acting on the perimetric area r, and pressure forces acting on the fore and aft crosssectional areas pr and ( p p) r, respectively. p By doing a force balance pr r ( p p) r r
6
7
8
9 5. Determine the head loss for a sudden expansion. Consider the control volume shown on the figure below and use conservation of mass and conservation of momentum. Mass Conservation VA VA m density is constant Momentum Conservation ( pa pa pa) pa M M a a b b c c 3 3 out in M M m V m V m V V V A V V out in out out in in ( 3 1) 3 3( 3 1) Assume that pa pb pc pa pa VA( V V )
10 Energy Equation (Bernoulli's equation) p1 V1 p3 V3 h g g g g L From momentum equation: p p V ( V V ) Substitute above in energy equation V1 V3 V3( V3 V1) ghl V1 V 3 Solve above for ghl V3 V3 V1 VA 1 1 From mass conservation: V3 A3 Substitute V 3 gh L VA V V A A3 A3 gh 1 L A 1 A A 1 A 1 1 A V1 A3 A3 A3 A3 A3 hl gh L A 1 The loss coefficient KL 1 V V 1 1 A3 g
11 6. Calculate the power supplied to the pump shown in Figure 3 if its efficiency 34 is 76%. Methyl alcohol ( 790 kg/m, Pa s ) is flowing at the rate 3 of 54 m /hr. The suction line is a standard 4 in steel pipe, 15 m long. The total length of in steel pipe in the discharge line is 00 m. Assume that the entrance from reservoir 1 is through a squarededged inlet and that the elbows are standard. The valve is a fully open globe valve. The roughness of the pipe is є= mm. Figure 3: Pump/pipeline configuration Consider a streamline joining the points 1 and. Applying the energy equation we obtain 1 W pump 1 p1 u1 gz1 p u gz ghl. Q p = p = p. If we take as the datum the point 1 then z 0 and z 10 m. 1 atm 1 If we further assume that u1 0 and u 0 the energy equation simpilfies to W Q gz gh. pump L
12 Given: Q D suction suction in= m m /hr m /s=0.015 m /s 15 m D discharge discharge in= m 00 m = 790 kg/m Pa s g= 9.81 m/s z 10 m 3 The only uknown in the equation for W pump V V V V V hl f f + KL + KL + KL D g D g g g g major losses major losses minor losses minor losses fully minor losses of minor losses suction discharge pipe entrance open globe valve the standard elbows pipe exit KL0.5 KL10 KL0.3 KL1 is + V KL g The loss coefficients can be obtained from a table, and the velocities from V = Q/( D / 4) / 3.14 / m/s suction discharge suction V = Q/( D / 4) / 3.14 / m/s discharge To find the major losses we need to find the Reynolds number and the relative roughness Re D f suction suction suction V suction D suction from Moody chart Re D f discharge discharge discharge 4 discharge discharge V D from Moody chart Substitute all above information in the equation for hl,calculate hl and finally substitue in equation for W pump
13 7. For the system shown in Figure 4, compute the power delivered by the 3 o pump to the water to pump m /s of water at 15 C to the tank. The air in the tank is at 76 kpa gauge pressure. Consider the friction loss in the 5ftlong discharge pipe, but neglect other losses. Then, redesign the system by using a larger pipe size to reduce the energy loss and reduce the power required to no more than 379 W. The roughness of the pipe is 4 є= and 1 in=0.054 m. Figure 4: Pump/pipeline configuration
14 8. In the turbulent region the friction factor associated with pipe flow is approximated by the formula: 0.5 f 5.74 log D Re Find an expression for the friction factor f for large Re number. For large Reynolds number (Re) above expression simplifies to f log because lim 0. Re 0.9 Re 3.7 D Liquid with specific gravity 3 g 10 kn/m is flowing in a vertical pipe. If the diameter of the pipe is D 15 cm and the viscosity of 3 the fluid is 310 Nm/s determine the direction of the flow and the mean velocity if the pipe relative roughness is / D The pressures shown are static pressures. Hint: Assume a high Reynolds number and verify. Energy Equation (Bernoulli's equation) p1 V1 p V z1 z h g g g g um where the losses are estimated using hl f D g and we have assumed that the flow is directed upwards. L
15 Using mass conservation and assuming uniform flow V V u 1 m. So Bernoulli's equation simplies to um um 0 10hL g g h h 1 L L Hence, our original assumption was wrong and the flow is directed downwards, i.e. p V p V g g g g h L 1 1 z1hl z 1 If we assume that the flow has a high Reynolds number then f log10 log D 3.7 h L 10 u 0.15 g m 0.1 um 1 um.89 m/s ud Verify Reynolds number Re=
16 9. Estimate the elevation required in the upper reservoir to produce a water discharge of 10 cfs in the system. What is the minimum pressure in the pipeline and what is the pressure there?
17 10. Water flows from a reservoir through a pipe 150mm diameter and 180m long to a point below the surface of the reservoir where it branches into two pipes, each 100mm in diameter (see Figure ). One of the pipes is 48m long discharging to atmosphere at a point below reservoir level and the other 60m long discharging to atmosphere 4m below reservoir level. Assuming that f 0.03 calculate the discharge from each pipe, neglecting all loses other than friction. 18m 180m 48m 60m 4m Figure : Reservoir pipeline configuration
18 11. The three waterfilled tanks shown in the figure (Figure P8.10 in textbook) are connected by pipes as indicated in the figure. If minor losses are neglected determine the flowrate in each pipe.
19
20 1. Water is to be pumped from one large, open tank to a second large, open tank as shown in the figure. The pipe diameter throughout is 15 cm and the total length of the pipe between the pipe entrance and exit is 61 m. Minor loss coefficients for the entrance, exit, and the elbow are shown on the figure, and the friction factor for the pipe can be assumed constant and equal to 0.0. A certain centrifugal pump having the performance characteristics shown in the figure is suggested as a good pump for this flow system. With this pump, what would be the flowrate between the tanks? Do you think this pump would be a good choice?
21
22
FLUID MECHANICS D203 SAE SOLUTIONS TUTORIAL 2 APPLICATIONS OF BERNOULLI SELF ASSESSMENT EXERCISE 1
FLUID MECHANICS D203 SAE SOLUTIONS TUTORIAL 2 APPLICATIONS OF BERNOULLI SELF ASSESSMENT EXERCISE 1 1. A pipe 100 mm bore diameter carries oil of density 900 kg/m3 at a rate of 4 kg/s. The pipe reduces
More informationHydraulics. B.E. (Civil), Year/Part: II/II. Tutorial solutions: Pipe flow. Tutorial 1
Hydraulics B.E. (Civil), Year/Part: II/II Tutorial solutions: Pipe flow Tutorial 1 by Dr. K.N. Dulal Laminar flow 1. A pipe 200mm in diameter and 20km long conveys oil of density 900 kg/m 3 and viscosity
More informationChapter (6) Energy Equation and Its Applications
Chapter (6) Energy Equation and Its Applications Bernoulli Equation Bernoulli equation is one of the most useful equations in fluid mechanics and hydraulics. And it s a statement of the principle of conservation
More informationFE Fluids Review March 23, 2012 Steve Burian (Civil & Environmental Engineering)
Topic: Fluid Properties 1. If 6 m 3 of oil weighs 47 kn, calculate its specific weight, density, and specific gravity. 2. 10.0 L of an incompressible liquid exert a force of 20 N at the earth s surface.
More informationReynolds, an engineering professor in early 1880 demonstrated two different types of flow through an experiment:
7 STEADY FLOW IN PIPES 7.1 Reynolds Number Reynolds, an engineering professor in early 1880 demonstrated two different types of flow through an experiment: Laminar flow Turbulent flow Reynolds apparatus
More informationLECTURE 6 ENERGY LOSSES IN HYDRAULIC SYSTEMS SELF EVALUATION QUESTIONS AND ANSWERS
LECTURE 6 ENERGY LOSSES IN HYDRAULIC SYSTEMS SELF EVALUATION QUESTIONS AND ANSWERS 1. What is the head loss ( in units of bars) across a 30mm wide open gate valve when oil ( SG=0.9) flow through at a
More informationLesson 6 Review of fundamentals: Fluid flow
Lesson 6 Review of fundamentals: Fluid flow The specific objective of this lesson is to conduct a brief review of the fundamentals of fluid flow and present: A general equation for conservation of mass
More informationPipe Flow. Lecture 17
Pipe Flow Lecture 7 Pipe Flow and the Energy Equation For pipe flow, the Bernoulli equation alone is not sufficient. Friction loss along the pipe, and momentum loss through diameter changes and corners
More informationPROPERTIES OF FLUIDS
Unit  I Chapter  PROPERTIES OF FLUIDS Solutions of Examples for Practice Example.9 : Given data : u = y y, = 8 Poise = 0.8 Pas To find : Shear stress. Step  : Calculate the shear stress at various
More informationChapter 6. Losses due to Fluid Friction
Chapter 6 Losses due to Fluid Friction 1 Objectives ä To measure the pressure drop in the straight section of smooth, rough, and packed pipes as a function of flow rate. ä To correlate this in terms of
More informationPiping Systems and Flow Analysis (Chapter 3)
Piping Systems and Flow Analysis (Chapter 3) 2 Learning Outcomes (Chapter 3) Losses in Piping Systems Major losses Minor losses Pipe Networks Pipes in series Pipes in parallel Manifolds and Distribution
More informationChapter 6. Losses due to Fluid Friction
Chapter 6 Losses due to Fluid Friction 1 Objectives To measure the pressure drop in the straight section of smooth, rough, and packed pipes as a function of flow rate. To correlate this in terms of the
More informationME 309 Fluid Mechanics Fall 2010 Exam 2 1A. 1B.
Fall 010 Exam 1A. 1B. Fall 010 Exam 1C. Water is flowing through a 180º bend. The inner and outer radii of the bend are 0.75 and 1.5 m, respectively. The velocity profile is approximated as C/r where C
More informationApplied Fluid Mechanics
Applied Fluid Mechanics 1. The Nature of Fluid and the Study of Fluid Mechanics 2. Viscosity of Fluid 3. Pressure Measurement 4. Forces Due to Static Fluid 5. Buoyancy and Stability 6. Flow of Fluid and
More informationFriction Factors and Drag Coefficients
Levicky 1 Friction Factors and Drag Coefficients Several equations that we have seen have included terms to represent dissipation of energy due to the viscous nature of fluid flow. For example, in the
More information150A Review Session 2/13/2014 Fluid Statics. Pressure acts in all directions, normal to the surrounding surfaces
Fluid Statics Pressure acts in all directions, normal to the surrounding surfaces or Whenever a pressure difference is the driving force, use gauge pressure o Bernoulli equation o Momentum balance with
More informationChapter (3) Water Flow in Pipes
Chapter (3) Water Flow in Pipes Water Flow in Pipes Bernoulli Equation Recall fluid mechanics course, the Bernoulli equation is: P 1 ρg + v 1 g + z 1 = P ρg + v g + z h P + h T + h L Here, we want to study
More informationChapter (3) Water Flow in Pipes
Chapter (3) Water Flow in Pipes Water Flow in Pipes Bernoulli Equation Recall fluid mechanics course, the Bernoulli equation is: P 1 ρg + v 1 g + z 1 = P ρg + v g + z h P + h T + h L Here, we want to study
More informationPart A: 1 pts each, 10 pts total, no partial credit.
Part A: 1 pts each, 10 pts total, no partial credit. 1) (Correct: 1 pt/ Wrong: 3 pts). The sum of static, dynamic, and hydrostatic pressures is constant when flow is steady, irrotational, incompressible,
More informationWhen water (fluid) flows in a pipe, for example from point A to point B, pressure drop will occur due to the energy losses (major and minor losses).
PRESSURE DROP AND OSSES IN PIPE When water (luid) lows in a pipe, or example rom point A to point B, pressure drop will occur due to the energy losses (major and minor losses). A B Bernoulli equation:
More informationChapter 8: Flow in Pipes
Objectives 1. Have a deeper understanding of laminar and turbulent flow in pipes and the analysis of fully developed flow 2. Calculate the major and minor losses associated with pipe flow in piping networks
More informationS.E. (Mech.) (First Sem.) EXAMINATION, (Common to Mech/Sandwich) FLUID MECHANICS (2008 PATTERN) Time : Three Hours Maximum Marks : 100
Total No. of Questions 12] [Total No. of Printed Pages 8 Seat No. [4262]113 S.E. (Mech.) (First Sem.) EXAMINATION, 2012 (Common to Mech/Sandwich) FLUID MECHANICS (2008 PATTERN) Time : Three Hours Maximum
More informationExam #2: Fluid Kinematics and Conservation Laws April 13, 2016, 7:00 p.m. 8:40 p.m. in CE 118
CVEN 311501 (Socolofsky) Fluid Dynamics Exam #2: Fluid Kinematics and Conservation Laws April 13, 2016, 7:00 p.m. 8:40 p.m. in CE 118 Name: : UIN: : Instructions: Fill in your name and UIN in the space
More informationViscous Flow in Ducts
Dr. M. Siavashi Iran University of Science and Technology Spring 2014 Objectives 1. Have a deeper understanding of laminar and turbulent flow in pipes and the analysis of fully developed flow 2. Calculate
More informationFigure 3: Problem 7. (a) 0.9 m (b) 1.8 m (c) 2.7 m (d) 3.6 m
1. For the manometer shown in figure 1, if the absolute pressure at point A is 1.013 10 5 Pa, the absolute pressure at point B is (ρ water =10 3 kg/m 3, ρ Hg =13.56 10 3 kg/m 3, ρ oil = 800kg/m 3 ): (a)
More informationV/ t = 0 p/ t = 0 ρ/ t = 0. V/ s = 0 p/ s = 0 ρ/ s = 0
UNIT III FLOW THROUGH PIPES 1. List the types of fluid flow. Steady and unsteady flow Uniform and nonuniform flow Laminar and Turbulent flow Compressible and incompressible flow Rotational and irrotational
More informationChapter Four fluid flow mass, energy, Bernoulli and momentum
41Conservation of Mass Principle Consider a control volume of arbitrary shape, as shown in Fig (41). Figure (41): the differential control volume and differential control volume (Total mass entering
More informationHydraulics and hydrology
Hydraulics and hydrology  project exercises  Class 4 and 5 Pipe flow Discharge (Q) (called also as the volume flow rate) is the volume of fluid that passes through an area per unit time. The discharge
More informationUNIT I FLUID PROPERTIES AND STATICS
SIDDHARTH GROUP OF INSTITUTIONS :: PUTTUR Siddharth Nagar, Narayanavanam Road 517583 QUESTION BANK (DESCRIPTIVE) Subject with Code : Fluid Mechanics (16CE106) Year & Sem: IIB.Tech & ISem Course & Branch:
More information2 Internal Fluid Flow
Internal Fluid Flow.1 Definitions Fluid Dynamics The study of fluids in motion. Static Pressure The pressure at a given point exerted by the static head of the fluid present directly above that point.
More informationHOMEWORK ASSIGNMENT ON BERNOULLI S EQUATION
AMEE 0 Introduction to Fluid Mechanics Instructor: Marios M. Fyrillas Email: m.fyrillas@frederick.ac.cy HOMEWORK ASSIGNMENT ON BERNOULLI S EQUATION. Conventional sprayguns operate by achieving a low pressure
More informationOnly if handing in. Name: Student No.: Page 2 of 7
UNIVERSITY OF TORONTO FACULTY OF APPLIED SCIENCE AND ENGINEERING FINAL EXAMINATION, DECEMBER 10, 2014 2:00 PM 2.5 HOURS CHE 211F FLUID MECHANICS EXAMINER: PROFESSOR D.G. ALLEN ANSWER ALL SEVEN (7) QUESTIONS
More information5 ENERGY EQUATION OF FLUID MOTION
5 ENERGY EQUATION OF FLUID MOTION 5.1 Introduction In order to develop the equations that describe a flow, it is assumed that fluids are subject to certain fundamental laws of physics. The pertinent laws
More informationReference : McCabe, W.L. Smith J.C. & Harriett P., Unit Operations of Chemical
1 Course materials (References) Textbook: Welty J. R., Wicks, C. E., Wilson, R. E., & Rorrer, G., Fundamentals of Momentum Heat, and Mass Transfer, 4th Edition, John Wiley & Sons.2000 Reference : McCabe,
More informationME 305 Fluid Mechanics I. Part 8 Viscous Flow in Pipes and Ducts. Flow in Pipes and Ducts. Flow in Pipes and Ducts (cont d)
ME 305 Fluid Mechanics I Flow in Pipes and Ducts Flow in closed conduits (circular pipes and noncircular ducts) are very common. Part 8 Viscous Flow in Pipes and Ducts These presentations are prepared
More informationCVE 372 HYDROMECHANICS EXERCISE PROBLEMS
VE 37 HYDROMEHNIS EXERISE PROLEMS 1. pump that has the characteristic curve shown in the accompanying graph is to be installed in the system shown. What will be the discharge of water in the system? Take
More informationSignature: (Note that unsigned exams will be given a score of zero.)
Neatly print your name: Signature: (Note that unsigned exams will be given a score of zero.) Circle your lecture section (1 point if not circled, or circled incorrectly): Prof. Dabiri Prof. Wassgren Prof.
More information9. Pumps (compressors & turbines) Partly based on Chapter 10 of the De Nevers textbook.
Lecture Notes CHE 31 Fluid Mechanics (Fall 010) 9. Pumps (compressors & turbines) Partly based on Chapter 10 of the De Nevers textbook. Basics (pressure head, efficiency, working point, stability) Pumps
More informationWater Circuit Lab. The pressure drop along a straight pipe segment can be calculated using the following set of equations:
Water Circuit Lab When a fluid flows in a conduit, there is friction between the flowing fluid and the pipe walls. The result of this friction is a net loss of energy in the flowing fluid. The fluid pressure
More informationρg 998(9.81) LV 50 V. d2g 0.062(9.81)
6.78 In Fig. P6.78 the connecting pipe is commercial steel 6 cm in diameter. Estimate the flow rate, in m 3 /h, if the fluid is water at 0 C. Which way is the flow? Solution: For water, take ρ = 998 kg/m
More informationFE Exam Fluids Review October 23, Important Concepts
FE Exam Fluids Review October 3, 013 mportant Concepts Density, specific volume, specific weight, specific gravity (Water 1000 kg/m^3, Air 1. kg/m^3) Meaning & Symbols? Stress, Pressure, Viscosity; Meaning
More informationFLUID MECHANICS PROF. DR. METİN GÜNER COMPILER
FLUID MECHANICS PROF. DR. METİN GÜNER COMPILER ANKARA UNIVERSITY FACULTY OF AGRICULTURE DEPARTMENT OF AGRICULTURAL MACHINERY AND TECHNOLOGIES ENGINEERING 1 5. FLOW IN PIPES 5.1.3. Pressure and Shear Stress
More informationME 305 Fluid Mechanics I. Chapter 8 Viscous Flow in Pipes and Ducts
ME 305 Fluid Mechanics I Chapter 8 Viscous Flow in Pipes and Ducts These presentations are prepared by Dr. Cüneyt Sert Department of Mechanical Engineering Middle East Technical University Ankara, Turkey
More informationPIPE FLOW. The Energy Equation. The first law of thermodynamics for a system is, in words = +
The Energy Equation PIPE FLOW The first law of thermodynamics for a system is, in words Time rate of increase of the total storage energy of the t Net time rate of energy addition by heat transfer into
More informations and FE X. A. Flow measurement B. properties C. statics D. impulse, and momentum equations E. Pipe and other internal flow 7% of FE Morning Session I
Fundamentals of Engineering (FE) Exam General Section Steven Burian Civil & Environmental Engineering October 26, 2010 s and FE X. A. Flow measurement B. properties C. statics D. impulse, and momentum
More informationEXPERIMENT NO: F5. Losses in Piping Systems
SJSU ME115  THERMAL ENGINEERING LAB EXPERIMENT NO: F5 Losses in Piping Systems Objective One of the most common problems in fluid mechanics is the estimation of pressure loss. It is the objective of this
More informationSourabh V. Apte. 308 Rogers Hall
Sourabh V. Apte 308 Rogers Hall sva@engr.orst.edu 1 Topics Quick overview of Fluid properties, units Hydrostatic forces Conservation laws (mass, momentum, energy) Flow through pipes (friction loss, Moody
More informationFACULTY OF CHEMICAL & ENERGY ENGINEERING FLUID MECHANICS LABORATORY TITLE OF EXPERIMENT: MINOR LOSSES IN PIPE (E4)
FACULTY OF CHEMICAL & ENERGY ENGINEERING FLUID MECHANICS LABORATORY TITLE OF EXPERIMENT: MINOR LOSSES IN PIPE (E4) 1 1.0 Objectives The objective of this experiment is to calculate loss coefficient (K
More informationChapter 10: Flow Flow in in Conduits Conduits Dr Ali Jawarneh
Chater 10: Flow in Conduits By Dr Ali Jawarneh Hashemite University 1 Outline In this chater we will: Analyse the shear stress distribution across a ie section. Discuss and analyse the case of laminar
More informationFluid Mechanics II Viscosity and shear stresses
Fluid Mechanics II Viscosity and shear stresses Shear stresses in a Newtonian fluid A fluid at rest can not resist shearing forces. Under the action of such forces it deforms continuously, however small
More informationApproximate physical properties of selected fluids All properties are given at pressure kn/m 2 and temperature 15 C.
Appendix FLUID MECHANICS Approximate physical properties of selected fluids All properties are given at pressure 101. kn/m and temperature 15 C. Liquids Density (kg/m ) Dynamic viscosity (N s/m ) Surface
More informationMODULE CODE: ENGG08021 INTRODUCTION TO THERMOFLUIDS. Date: 15 January 2016 Time: 10:00 12:00
School of Engineering & Computing Session 201516 Paisley Campus Trimester 1 MODULE CODE: ENGG08021 INTRODUCTION TO THERMOFLUIDS Date: 15 January 2016 Time: 10:00 12:00 Attempt FOUR QUESTIONS IN TOTAL
More informationPIPE FLOWS: LECTURE /04/2017. Yesterday, for the example problem Δp = f(v, ρ, μ, L, D) We came up with the non dimensional relation
/04/07 ECTURE 4 PIPE FOWS: Yesterday, for the example problem Δp = f(v, ρ, μ,, ) We came up with the non dimensional relation f (, ) 3 V or, p f(, ) You can plot π versus π with π 3 as a parameter. Or,
More informationPIPE FLOW. General Characteristic of Pipe Flow. Some of the basic components of a typical pipe system are shown in Figure 1.
PIPE FLOW General Characteristic of Pipe Flow Figure 1 Some of the basic components of a typical pipe system are shown in Figure 1. They include the pipes, the various fitting used to connect the individual
More informationLecture 3 The energy equation
Lecture 3 The energy equation Dr Tim Gough: t.gough@bradford.ac.uk General information Lab groups now assigned Timetable up to week 6 published Is there anyone not yet on the list? Week 3 Week 4 Week 5
More informationFluid Mechanics c) Orificemeter a) Viscous force, Turbulence force, Compressible force a) Turbulence force c) Integration d) The flow is rotational
Fluid Mechanics 1. Which is the cheapest device for measuring flow / discharge rate. a) Venturimeter b) Pitot tube c) Orificemeter d) None of the mentioned 2. Which forces are neglected to obtain Euler
More informationSTEADY FLOW THROUGH PIPES DARCY WEISBACH EQUATION FOR FLOW IN PIPES. HAZEN WILLIAM S FORMULA, LOSSES IN PIPELINES, HYDRAULIC GRADE LINES AND ENERGY
STEADY FLOW THROUGH PIPES DARCY WEISBACH EQUATION FOR FLOW IN PIPES. HAZEN WILLIAM S FORMULA, LOSSES IN PIPELINES, HYDRAULIC GRADE LINES AND ENERGY LINES 1 SIGNIFICANCE OF CONDUITS In considering the convenience
More informationCHAPTER 3 BASIC EQUATIONS IN FLUID MECHANICS NOOR ALIZA AHMAD
CHAPTER 3 BASIC EQUATIONS IN FLUID MECHANICS 1 INTRODUCTION Flow often referred as an ideal fluid. We presume that such a fluid has no viscosity. However, this is an idealized situation that does not exist.
More informationProf. Scalo Prof. Vlachos Prof. Ardekani Prof. Dabiri 08:30 09:20 A.M 10:30 11:20 A.M. 1:30 2:20 P.M. 3:30 4:20 P.M.
Page 1 Neatly print your name: Signature: (Note that unsigned exams will be given a score of zero.) Circle your lecture section (1 point if not circled, or circled incorrectly): Prof. Scalo Prof. Vlachos
More informationEngineers Edge, LLC PDH & Professional Training
510 N. Crosslane Rd. Monroe, Georgia 30656 (770) 2666915 fax (678) 6431758 Engineers Edge, LLC PDH & Professional Training Copyright, All Rights Reserved Engineers Edge, LLC Pipe FlowFriction Factor
More informationP & I Design Limited. 2 Reed Street, Gladstone Industrial Estate, Thornaby, TS17 7AF. Tel: +44 (0) Fax: +44 (0)
ump Sizing & Rating USER MANUAL & I Design Limited Reed Street, Gladstone Industrial Estate, Thornaby, TS7 7AF. Tel: +44 (0) 64 67444 Fax: +44 (0) 64 66447 www.pidesign.co.uk Support: sales@pidesign.co.uk
More informationMULTIPLECHOICE PROBLEMS:(Two marks per answer) (Circle the Letter Beside the Most Correct Answer in the Questions Below.)
MULTIPLECHOICE PROLEMS:(Two marks per answer) (Circle the Letter eside the Most Correct Answer in the Questions elow.) 1. The absolute viscosity µ of a fluid is primarily a function of: a. Density. b.
More informationFLOW MEASUREMENT IN PIPES EXPERIMENT
University of Leicester Engineering Department FLOW MEASUREMENT IN PIPES EXPERIMENT Page 1 FORMAL LABORATORY REPORT Name of the experiment: FLOW MEASUREMENT IN PIPES Author: Apollin nana chaazou Partner
More informationLesson 37 Transmission Of Air In Air Conditioning Ducts
Lesson 37 Transmission Of Air In Air Conditioning Ducts Version 1 ME, IIT Kharagpur 1 The specific objectives of this chapter are to: 1. Describe an Air Handling Unit (AHU) and its functions (Section 37.1).
More informationINSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad AERONAUTICAL ENGINEERING QUESTION BANK : AERONAUTICAL ENGINEERING.
Course Name Course Code Class Branch INSTITUTE OF AERONAUTICAL ENGINEERING Dundigal, Hyderabad  00 0 AERONAUTICAL ENGINEERING : Mechanics of Fluids : A00 : III B. Tech Year : 0 0 Course Coordinator
More informationChapter 4 DYNAMICS OF FLUID FLOW
Faculty Of Engineering at Shobra nd Year Civil  016 Chapter 4 DYNAMICS OF FLUID FLOW 41 Types of Energy 4 Euler s Equation 43 Bernoulli s Equation 44 Total Energy Line (TEL) and Hydraulic Grade Line
More informationUNIT II Real fluids. FMM / KRG / MECH / NPRCET Page 78. Laminar and turbulent flow
UNIT II Real fluids The flow of real fluids exhibits viscous effect that is they tend to "stick" to solid surfaces and have stresses within their body. You might remember from earlier in the course Newtons
More informationCHAPTER THREE FLUID MECHANICS
CHAPTER THREE FLUID MECHANICS 3.1. Measurement of Pressure Drop for Flow through Different Geometries 3.. Determination of Operating Characteristics of a Centrifugal Pump 3.3. Energy Losses in Pipes under
More informationCHAPTER 2 Pressure and Head
FLUID MECHANICS Gaza, Sep. 2012 CHAPTER 2 Pressure and Head Dr. Khalil Mahmoud ALASTAL Objectives of this Chapter: Introduce the concept of pressure. Prove it has a unique value at any particular elevation.
More informationMass of fluid leaving per unit time
5 ENERGY EQUATION OF FLUID MOTION 5.1 Eulerian Approach & Control Volume In order to develop the equations that describe a flow, it is assumed that fluids are subject to certain fundamental laws of physics.
More informationHydraulics for Urban Storm Drainage
Urban Hydraulics Hydraulics for Urban Storm Drainage Learning objectives: understanding of basic concepts of fluid flow and how to analyze conduit flows, free surface flows. to analyze, hydrostatic pressure
More informationRate of Flow Quantity of fluid passing through any section (area) per unit time
Kinematics of Fluid Flow Kinematics is the science which deals with study of motion of liquids without considering the forces causing the motion. Rate of Flow Quantity of fluid passing through any section
More informationR09. d water surface. Prove that the depth of pressure is equal to p +.
Code No:A109210105 R09 SET1 B.Tech II Year  I Semester Examinations, December 2011 FLUID MECHANICS (CIVIL ENGINEERING) Time: 3 hours Max. Marks: 75 Answer any five questions All questions carry equal
More informationLecture 2 Flow classifications and continuity
Lecture 2 Flow classifications and continuity Dr Tim Gough: t.gough@bradford.ac.uk General information 1 No tutorial week 3 3 rd October 2013 this Thursday. Attempt tutorial based on examples from today
More informationSteven Burian Civil & Environmental Engineering September 25, 2013
Fundamentals of Engineering (FE) Exam Mechanics Steven Burian Civil & Environmental Engineering September 25, 2013 s and FE Morning ( Mechanics) A. Flow measurement 7% of FE Morning B. properties Session
More informationApplied Fluid Mechanics
Applied Fluid Mechanics 1. The Nature of Fluid and the Study of Fluid Mechanics 2. Viscosity of Fluid 3. Pressure Measurement 4. Forces Due to Static Fluid 5. Buoyancy and Stability 6. Flow of Fluid and
More informationFluid Mechanics. du dy
FLUID MECHANICS Technical English  I 1 th week Fluid Mechanics FLUID STATICS FLUID DYNAMICS Fluid Statics or Hydrostatics is the study of fluids at rest. The main equation required for this is Newton's
More informationModelling of dispersed, multicomponent, multiphase flows in resource industries. Section 3: Examples of analyses conducted for Newtonian fluids
Modelling of dispersed, multicomponent, multiphase flows in resource industries Section 3: Examples of analyses conducted for Newtonian fluids Globex Julmester 017 Lecture # 04 July 017 Agenda Lecture
More informationA Model Answer for. Problem Set #7
A Model Answer for Problem Set #7 Pipe Flow and Applications Problem.1 A pipeline 70 m long connects two reservoirs having a difference in water level of 6.0 m. The pipe rises to a height of 3.0 m above
More informationMULTIPLECHOICE PROBLEMS :(Two marks per answer) (Circle the Letter Beside the Most Correct Answer in the Questions Below.)
Test Midterm 1 F2013 MULTIPLECHOICE PROBLEMS :(Two marks per answer) (Circle the Letter Beside the Most Correct nswer in the Questions Below.) 1. The absolute viscosity µ of a fluid is primarily a function
More informationQ1 Give answers to all of the following questions (5 marks each):
FLUID MECHANICS First Year Exam Solutions 03 Q Give answers to all of the following questions (5 marks each): (a) A cylinder of m in diameter is made with material of relative density 0.5. It is moored
More informationReview of pipe flow: Friction & Minor Losses
ENVE 204 Lecture 1 Review of pipe flow: Friction & Minor Losses Assist. Prof. Neslihan SEMERCİ Marmara University Department of Environmental Engineering Important Definitions Pressure Pipe Flow: Refers
More informationDepartment of Mechanical Engineering
Department of Mechanical Engineering AMEE401 / AUTO400 Aerodynamics Instructor: Marios M. Fyrillas Email: eng.fm@fit.ac.cy HOMEWORK ASSIGNMENT #2 QUESTION 1 Clearly there are two mechanisms responsible
More informationIntroduction to Heat and Mass Transfer. Week 14
Introduction to Heat and Mass Transfer Week 14 Next Topic Internal Flow» Velocity Boundary Layer Development» Thermal Boundary Layer Development» Energy Balance Velocity Boundary Layer Development Velocity
More informationBACHELOR OF TECHNOLOGY IN MECHANICAL ENGINEERING (COMPUTER INTEGRATED MANUFACTURING)
No. of Printed Pages : 6 BME028 BACHELOR OF TECHNOLOGY IN MECHANICAL ENGINEERING (COMPUTER INTEGRATED MANUFACTURING) TermEnd Examination December, 2011 00792 BME028 : FLUID MECHANICS Time : 3 hours
More information10.52 Mechanics of Fluids Spring 2006 Problem Set 3
10.52 Mechanics of Fluids Spring 2006 Problem Set 3 Problem 1 Mass transfer studies involving the transport of a solute from a gas to a liquid often involve the use of a laminar jet of liquid. The situation
More informationChapter Four Hydraulic Machines
Contents 1 Introduction.  Pumps. Chapter Four Hydraulic Machines (لفرع الميكانيك العام فقط ( Turbines. 3 4 Cavitation in hydraulic machines. 5 Examples. 6 Problems; sheet No. 4 (Pumps) 7 Problems;
More informationHOW TO GET A GOOD GRADE ON THE MME 2273B FLUID MECHANICS 1 EXAM. Common mistakes made on the final exam and how to avoid them
HOW TO GET A GOOD GRADE ON THE MME 2273B FLUID MECHANICS 1 EXAM Common mistakes made on the final exam and how to avoid them HOW TO GET A GOOD GRADE ON THE MME 2273B EXAM Introduction You now have a lot
More informationACCOUNTING FOR FRICTION IN THE BERNOULLI EQUATION FOR FLOW THROUGH PIPES
ACCOUNTING FOR FRICTION IN THE BERNOULLI EQUATION FOR FLOW THROUGH PIPES Some background information first: We have seen that a major limitation of the Bernoulli equation is that it does not account for
More informationVALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur
VALLIAMMAI ENGINEERING COLLEGE SRM Nagar, Kattankulathur 603 203 DEPARTMENT OF CIVIL ENGINEERING QUESTION BANK III SEMESTER CE 8302 FLUID MECHANICS Regulation 2017 Academic Year 2018 19 Prepared by Mrs.
More informationExperiment (4): Flow measurement
Experiment (4): Flow measurement Introduction: The flow measuring apparatus is used to familiarize the students with typical methods of flow measurement of an incompressible fluid and, at the same time
More informationExercise sheet 5 (Pipe flow)
Exercise sheet 5 (Pipe flow) last edited June 4, 2018 These lecture notes are based on textbooks by White [13], Çengel & al.[16], and Munson & al.[18]. Except otherwise indicated, we assume that fluids
More informationHydraulic (Piezometric) Grade Lines (HGL) and
Hydraulic (Piezometric) Grade Lines (HGL) and Energy Grade Lines (EGL) When the energy equation is written between two points it is expresses as in the form of: Each term has a name and all terms have
More informationChapter 10 Flow in Conduits
Chapter 10 Flow in Conduits 10.1 Classifying Flow Laminar Flow and Turbulent Flow Laminar flow Unpredictable Turbulent flow Near entrance: undeveloped developing flow In developing flow, the wall shear
More informationConvection. forced convection when the flow is caused by external means, such as by a fan, a pump, or atmospheric winds.
Convection The convection heat transfer mode is comprised of two mechanisms. In addition to energy transfer due to random molecular motion (diffusion), energy is also transferred by the bulk, or macroscopic,
More informationAtmospheric pressure. 9 ft. 6 ft
Name CEE 4 Final Exam, Aut 00; Answer all questions; 145 points total. Some information that might be helpful is provided below. A Moody diagram is printed on the last page. For water at 0 o C (68 o F):
More informationCIVE HYDRAULIC ENGINEERING PART II Pierre Julien Colorado State University
1 CIVE 401  HYDRAULIC ENGINEERING PART II Pierre Julien Colorado State University Problems with and are considered moderate and those with are the longest and most difficult. In 2018 solve the problems
More informationREE 307 Fluid Mechanics II. Lecture 1. Sep 27, Dr./ Ahmed Mohamed Nagib Elmekawy. Zewail City for Science and Technology
REE 307 Fluid Mechanics II Lecture 1 Sep 27, 2017 Dr./ Ahmed Mohamed Nagib Elmekawy Zewail City for Science and Technology Course Materials drahmednagib.com 2 COURSE OUTLINE Fundamental of Flow in pipes
More informationChapter 7 FLOW THROUGH PIPES
Chapter 7 FLOW THROUGH PIPES 71 Friction Losses of Head in Pipes 72 Secondary Losses of Head in Pipes 73 Flow through Pipe Systems 48 71 Friction Losses of Head in Pipes: There are many types of losses
More informationEXPERIMENT No.1 FLOW MEASUREMENT BY ORIFICEMETER
EXPERIMENT No.1 FLOW MEASUREMENT BY ORIFICEMETER 1.1 AIM: To determine the coefficient of discharge of the orifice meter 1.2 EQUIPMENTS REQUIRED: Orifice meter test rig, Stopwatch 1.3 PREPARATION 1.3.1
More information